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Find the first and second excitation pot...

Find the first and second excitation potentials of an atom when its ionisation potential is 122.4 V .

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To find the first and second excitation potentials of an atom when its ionization potential is given as 122.4 V, we can follow these steps: ### Step 1: Understand Ionization Potential The ionization potential (IP) is the energy required to remove the most loosely bound electron from an atom. It is given as 122.4 V. ### Step 2: Use the Formula for Ionization Potential The formula for ionization potential is given by: \[ ...
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MOTION-ATOMIC STRUCTURE & X-RAY -Exercise - 2
  1. Find the first and second excitation potentials of an atom when its io...

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  2. Energy levels A, B, C of a certain atom corresponding to increasing va...

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  3. What is the minimum wavelength of X–rays

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  4. What is the approximate ratio of wavelength of radiation K(alpha(1)) a...

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  5. To increase the hardness of X–rays in coolidge tube we should –

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  6. The solution of Bragg's equation is possible if :

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  7. For X–ray diffraction, order of wave length is

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  8. Hard X–rays for the study of fractures in bones should have a minimum ...

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  9. X-rays were discovered by

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  10. Which of the following is the wave length of X– ray:

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  11. For producing the X–rays, what is the value of voltage (nearly), which...

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  12. For first order X–ray diffraction if lattice constant is 3 xx 10^(–8) ...

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  13. lambda("min") of X-rays depends on :-

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  14. The order of energy of X-ray photon is :-

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  15. If vacuum tube is operated at 6.4 kV, what is the wavelength of X-ray ...

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  16. When electron is incident on molyblednum then by changing energy of el...

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  17. The groud state energy of hydrogen atom is -13.6 eV. When its electron...

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  18. The ionization enegry of the electron in the hydrogen atom in its grou...

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  19. In a Rutherford scattering experiment when a projectile of change Z(1)...

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  20. An electrons of a stationary hydrogen aton passes form the fifth enegr...

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  21. Ratio of longest wavelengths corresponding to Lyman and Balmer series ...

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