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Electrons with de- Broglie wavelength la...

Electrons with de- Broglie wavelength `lambda` fall on the target in an X- rays tube . The cut off wavelength of the emitted X- rays is

A

`lambda_(0)=lambda0`

B

`lambda_(0)=(2mc lambda^(2))/(h)`

C

`lambda_(0)=(2h)/(mc)`

D

`lambda_(0)=(2m^(2)c^(2)lambda^(2))/(h^(2))`

Text Solution

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The correct Answer is:
B
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