Find the final charge on each capacitor if they are connected as shown in the figure.

Explanation

(a) Initially
Finally let q charge flows clockwise then Now applying KVL
`(+q)/(C_(1))+((10+q))/(C_(2))-((100-q))/(C_(3))=0`

`rArr q/2+(10+q)/(2)-(100-q)/(5)=0`
5q+50+5q-200+2q=0
12q-150=0
`rArr q=75/6 muC`
So finally
(b) Find heat loss in the above circuit.
`triangle="Energy [initially-finally] on capacitor"`
`=[{1/2xx5xx(20)^(2)+1/2xx2xx(5)^(2)}-{1/2xx((525)/(6))^(2)+1/5+1/2xx((75)/(6))^(2)xx1/2+1/2((135)/(6))^(2)xx1/2}]xx 10^(-6)J`