In the given circuit find out the charge on each capacitor. (Initially they are uncharged)

Explanation

Let potential at A is 0, so at D it is 30 V, at F it is 10 V and at point G potential is -25V. Now apply Kirchhoff's Ist law at point E. (total charge of all the plates connected to 'E' must be same as before i.e. 0)
`therefore (x-10)+(x-30)2+(x+25)2=0`
5x=20, x=4
Final charges: `Q_(2muF)=(30-4)2=52muC`

`Q_(1muF)=(10-4)=6muC`
`Q_(2muF)=(4-(-25))2=58muC`