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Two capacitors of capacitance `1 muF and 2muF` are charged to potential difference 20 V and 15 V as shown in figure. If now terminal B and C are connected together terminal A with positive of battery and D with negative terminal of battery then find out final charges on both the capacitor.

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Now applying kirchoff voltage law `(-(20+q))/(1)-(30+q)/(2)+30=0`
`-40-2q-30-q=-60`
3q=-10
Charge flow `=-10/3 muC`.
Charge on capacitor of capacitance `1muF=20+q=(50)/(3)`
Charge on capacitor of capacitance `2muF=30+q=80/3`
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