In the circuit shown the capacitors are `C_(1)=15muF, C_(2)=10muF and C_(3)=25 muF`. Find

the charge on each capacitor and

Explanation

Q=Total charge supplied by the cell =CV= `(12.5 xx 10)muC=125muC`
Charge on `C_(1)=Q_(1)=((C_(1))/(C_(1)+C_(2)))Q=((15)/(15+10))xx 125=75muC`
Charge on `C_(2)=Q_(2)=((C_(2))/(C_(1)+C_(2)))Q=((10)/(15+10))xx 125=50muC`
Charge on `C_(3)=Q=125muC`