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In the circuit shown the capacitors are ...

In the circuit shown the capacitors are `C_(1)=15muF, C_(2)=10muF and C_(3)=25 muF`. Find

the potential difference across each capacitor.

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p.d. across `C_(1)=V_(1)=Q_(1)/C_(1)=75/15 =5V`
p.d. across `C_(2)=V_(2)=V_(1)=5V`
p.d. across `C_(3)=V_(3)=(Q_(3))/(C_(3))=(125)/(25)=5V`
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MOTION-10 ROTATIONAL-Exercise - 4 (Level - II)
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