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At t =0 switch S1 is closed and remains ...

At t =0 switch `S_1` is closed and remains closed for a long time and `S_2` remains open. Now `S_1` is opened and `S_2` is closed. Find out

Charge on the capacitor long after that moment.

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After a long time, i=0
`V_(B)-V_(A)=V_(D)-V_(A)=-2e`
`therefore Q=C(-2epsi-0)=-2epsiC`
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MOTION-10 ROTATIONAL-Exercise - 4 (Level - II)
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