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The earth receives solar energy at the r...

The earth receives solar energy at the rate of 2 cal `Cm^(-2)` per minute. Assuming theradiation tobeblack body in character, estimate the surface temperature of the sun. Given that `sigma =5.67 xx10^(-8) Wm^(-2)K^(-4)` and angular diameter of the sun =32 minute of arc.

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To solve the problem, we need to estimate the surface temperature of the Sun based on the solar energy received by the Earth. Here’s a step-by-step solution: ### Step 1: Convert the solar energy received by Earth to SI units The energy received by the Earth is given as 2 calories per cm² per minute. We need to convert this to watts per m². 1 calorie = 4.184 joules 1 cm² = 10⁻⁴ m² 1 minute = 60 seconds ...
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The sun radiates maximum energy at wavelength 4753 Å . Estimate the surface temperature of the sun, if b = 2.888 xx 10^(-3) mK .

At what temperature, a perfect black body will radiate energy at the rate of 6.48 W//cm^2 . Take, sigma = 5.67 xx 10^(-8) Wm^(-2) K^(-4)

Knowledge Check

  • The radiant power of a furnace of surface area of 0.6m^(2) is 34.2KW The temperature of the furance s [sigma = 5.7 xx 10^(-8) Wm^(-2) K^(-4) .

    A
    `3400K`
    B
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    D
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  • Calculate the temperature at which a perfect black body radiates at the rate of 1 W cm^(-2) , value of Stefan's constant, sigma = 5.67 xx 10^(-8) W m^(-2)K^(-4)

    A
    576 K
    B
    648 K
    C
    695 K
    D
    766 K
  • Calculate the temperature at which a perfect black body radiates at the rate of 1 W cm^(-2) , value of Stefan's constant, sigma = 5.67 xx 10^(-5) W m^(-2) K^(-8)

    A
    `576 K`
    B
    `648 K`
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    Calculate the temperature (in K) at which a perfect black body radiates energy at the rate of 5.67W cm^(-2) . Given sigma = 5.67 xx 10^(8)Wm^(-2)K^(-4) .

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