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A compound slab is made of two parallel plates of copper and brass of the same thickness and having thermal conductivities in the ratio `4:1`. The free face of copper is at `0^(@)C`. The temperature of the internal is `20^(@)C`. What is the temperature of the free face of brass?

A

`0^(@)C`

B

`20^(@)C`

C

`40^(@)C`

D

`100^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
D

`(k_(cu))/(k_(b) = (4)/(1)`
Let temperature of free surface ofbrass is `T^(@)C`
`(k_(cu)A(20 -0))/(l) =(k_(b)A(T-20))/(l)`
`rArr 4k_(b) (20) = k_(b)(T-20)`
`rArr ` 80 = T- 20
`rArr T = 100^(@)C`
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