The energy emitted per second by a black body at `27^(@)C` is 10 J. If the temperature of the black body is increased to `327^(@)C` , the energy emitted per second will be

Options

A. 20 J
B. 40 J
C. 80 J
D. 160 J

Answer

D

Explanation

We use `PpropT^(4)`
`implies (P_(1))/(P_(2))=(T_(1)^(4))/(T_(2)^(4))`
`imples (10)/(P_(2))=(27+273)^(4)/((327+273)^(4))`
`implies (10)/(P_(2))=(300/(600))^(4)=(1)/(16)`
`implies P_(2)=160J//s`
Thus, energy emitted per second = 160J