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A heat flux of 4000 J/s is to be passed ...

A heat flux of 4000 J/s is to be passed through a copper rod of length 10 cm and area of cross section `100cm^2`. The thermal conductivity of copper is `400W//m//^(@)C` The two ends of this rod must be kept at a temperature difference of

A

`1^(@)C`

B

`10^(@)C`

C

`100^(@)C`

D

`1000^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
We use `H=(Q)/(t) =(kA(Delta T)/(L)`
`rArr4000 = (400 xx (100 xx 10^(-4)) xx Delta T).(0.1)`
`rArr`` Delta T = 100^(@)C`
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