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The thermal powered density u is generat...

The thermal powered density u is generated uniformly inside a uniform sphere of radius R and thermal conductivity Find the temperature distribution in the sphere when the steady state temperature at the surface is `T_(0)`.

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To find the temperature distribution in a uniform sphere with a uniform thermal power density \( U \) generated inside it, we can follow these steps: ### Step 1: Understand the Problem We have a uniform sphere of radius \( R \) and thermal conductivity \( k \). Inside this sphere, there is a uniform thermal power density \( U \). The steady-state temperature at the surface of the sphere is given as \( T_0 \). We need to find the temperature distribution \( T(r) \) within the sphere. ### Step 2: Set Up the Heat Equation In a steady state, the heat generated inside the sphere must equal the heat conducted to the surface. The heat conduction can be described by Fourier's law: \[ \frac{dq}{dt} = -kA \frac{dT}{dr} \] where \( A \) is the surface area of a sphere at radius \( r \), which is \( 4\pi r^2 \). ### Step 3: Heat Generation Inside the Sphere The heat generated inside the sphere can be expressed as: \[ \frac{dq}{dt} = U \cdot V \] where \( V \) is the volume of the sphere of radius \( r \), given by \( \frac{4}{3}\pi r^3 \). ### Step 4: Equate Heat Generation and Heat Conduction Setting the two expressions for heat equal gives: \[ -k \cdot 4\pi r^2 \frac{dT}{dr} = U \cdot \frac{4}{3}\pi r^3 \] ### Step 5: Simplify the Equation We can simplify this equation by canceling \( 4\pi \) from both sides: \[ -k r^2 \frac{dT}{dr} = \frac{U}{3} r^3 \] Rearranging gives: \[ \frac{dT}{dr} = -\frac{U}{3k} r \] ### Step 6: Integrate the Equation Integrating both sides with respect to \( r \): \[ \int dT = -\frac{U}{3k} \int r \, dr \] This results in: \[ T = -\frac{U}{6k} r^2 + C \] where \( C \) is the constant of integration. ### Step 7: Apply Boundary Conditions We know that at the surface of the sphere (where \( r = R \)), the temperature \( T(R) = T_0 \): \[ T_0 = -\frac{U}{6k} R^2 + C \] Solving for \( C \): \[ C = T_0 + \frac{U}{6k} R^2 \] ### Step 8: Write the Final Temperature Distribution Substituting \( C \) back into the equation for \( T \): \[ T(r) = -\frac{U}{6k} r^2 + T_0 + \frac{U}{6k} R^2 \] This simplifies to: \[ T(r) = T_0 + \frac{U}{6k} (R^2 - r^2) \] ### Final Answer The temperature distribution in the sphere is given by: \[ T(r) = T_0 + \frac{U}{6k} (R^2 - r^2) \]
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