Find the roots of the quadratic equations by using the quadratic formula in each of the following
`-3x^(2)+5x+12=0`

Explanation

Given equation is `-3x^(2)+5x+12=0`
On comparing with `ax^(2)+bx+c=0` we get
`a=-3, b=5` and `c=12`
By quadratic formula `x=(-b+-sqrt(b^(2)-4ac))/(2a)`
`(-(5)+-sqrt((5)^(2)-4(-3)(12)))/(2(-3))`
`=(5+-sqrt(25+144))/(-6)=(-5+-sqrt(169))/(-6)`
`=(-5-13)/(-6)=8/(-6), (-18)/(-6)=-4/3,3`
So `-4/3` and 3 are two roots of the given equation.