A pole 6 m high casts a shadow 2`sqrt 3` m long on the ground, then find the angle oi elevation of the sun.

Options

A. `60^(@)`
B. `45^(@)`
C. `30^(@)`
D. `90^(@)`

Answer

A

Explanation

Let BC=6 m be the height of the pole and AB`=2sqrt(3)` m be the length of the shadow on the ground. Let the Sun's make an angle `theta` on the ground.
Now, in `DeltaABC`, `tantheta=(BC)/(AB)`
`rArr tantheta=6/(2sqrt(3))=3/sqrt(3).sqrt(3)/sqrt(3)`
`rArr tantheta=(3sqrt(3))/(3)= sqrt(3)=tan60^(@)` `[therefore tan 60^(@)=sqrt(3)]`
`therefore theta=60^(@)`
Hence, the Sun's elevation is `60^(@)`.