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If n(A)=n(B)=3, then how many bijective ...

If `n(A)=n(B)=3`, then how many bijective functions from A to B can be formed?

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To find the number of bijective functions from set A to set B when both sets have the same number of elements, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the cardinality of sets A and B**: Given that \( n(A) = n(B) = 3 \), we know both sets have 3 elements. 2. **Understand the concept of bijective functions**: A bijective function is a one-to-one correspondence between the elements of set A and set B. This means every element in A is paired with a unique element in B, and vice versa. 3. **Use the formula for the number of bijective functions**: The number of bijective functions from a set with \( n \) elements to another set with \( n \) elements is given by \( n! \) (n factorial). 4. **Calculate \( n! \) for \( n = 3 \)**: Here, since \( n = 3 \), we calculate \( 3! \): \[ 3! = 3 \times 2 \times 1 = 6 \] 5. **Conclusion**: Therefore, the total number of bijective functions from set A to set B is 6. ### Final Answer: The number of bijective functions from A to B is **6**.
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