Home
Class 11
PHYSICS
The displacement of a body is proportion...

The displacement of a body is proportional to `t^(3)`, where t is time elapsed. What is the nature of acceleration - time graph of the body?

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the relationship between displacement, velocity, and acceleration based on the given information that displacement is proportional to \( t^3 \). ### Step-by-Step Solution: 1. **Understanding Displacement**: - We are given that the displacement \( x \) of a body is proportional to \( t^3 \). - This can be expressed mathematically as: \[ ...
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS

    CBSE COMPLEMENTARY MATERIAL|Exercise 3 Marks|11 Videos
  • KINEMATICS

    CBSE COMPLEMENTARY MATERIAL|Exercise 5 Marks|2 Videos
  • KINEMATICS

    CBSE COMPLEMENTARY MATERIAL|Exercise M.C.Q.|20 Videos
  • GRAVITATION

    CBSE COMPLEMENTARY MATERIAL|Exercise MULTIPLE CHOICE QUESTIONS|19 Videos
  • KINETIC THEORY OF GASES

    CBSE COMPLEMENTARY MATERIAL|Exercise Objective question|20 Videos

Similar Questions

Explore conceptually related problems

The displacement of a body is gives to be proporticonal to the cube of time elapsed. What is the nature of the acceleration of the body ?

The displacement of a body is given to be proportional to the cube of time elapsed. The magnitude of the acceleration of the body is

A variable force F acts on a body which is free to move. The displacement of the body is proportional to t^(3) , where t = time. The power delivered by F to the body will be proportional to

If the displacement-time graph of a body is a straight line parallel to the time axis, what is the nature of motion of the body?

Assertion: The slope of displacement-time graph of a body moving with high velocity is steeper than the slope of displacement-time graph of a body with low velocity. Reason: Slope of displacement-time graph = Velocity of the body.

The displacement of a body is given by r=sqrt(a^(2)-t^(2))+t cost^(2) , where t is the time and a is constant. Its velosity is :

The distance covered by a moving body is directly proportional to the square to the time. The acceleration of the body is

The position of a particle moving on a straight line is proportional to the cube of the time elapsed. How does the acceleration of the particle depend on time elapsed?

The angular displacement of a particle is given by theta = t^3 + 2t +1 , where t is time in seconds. Its angular acceleration at t=2s is

The displacement of a body is given by s=(1)/(2)g t^(2) where g is acceleration due to gravity. The velocity of the body at any time t is