The displacement x of a particle varies with time as `x = 4t^(2) – 15t + 25`. Find the position, velocity and acceleration of the particle at t = 0.

Explanation

To solve the problem, we need to find the position, velocity, and acceleration of a particle whose displacement \( x \) varies with time \( t \) according to the equation:

\[ x = 4t^2 - 15t + 25 \]

We will evaluate these quantities at \( t = 0 \).

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