The resultant vector of `vec(P)` and `vec(Q)` is `vec(R)`. On reversing the direction of `vec(Q)`, the resultant vector becomes `vec(S)`. Show that : `R^(2) +S^(2) = 2(P^(2)+Q^(2))`

Two vectors vec P and vec Q

The resultant of vec(A)+vec(B) is vec(R )_(1) . On reversing the vector vec(B) , the resultant becomes vec(R )_(2) . What is the value of R_(1)^(2)+R_(2)^(2) ?

The resultant of two vectors vec(P) and vec(Q) is vec(R ) . If the magnitude of vec(Q) is doubled, the new resultant vector becomes perpendicular to vec(P) . Then, the magnitude of vec(R ) is equal to

The resultant of two vectors vec(P) and vec(Q) is vec(R) . If vec(Q) is doubled then the new resultant vector is perpendicular to vec(P) . Then magnitude of vec(R) is :-

The resultant vec(P) and vec(Q) is perpendicular to vec(P) . What is the angle between vec(P) and vec(Q) ?

if vec(P) xx vec(R ) = vec(Q) xx vec(R ) , then

If |vec(P) + vec(Q)| = |vec(P) - vec(Q)| , find the angle between vec(P) and vec(Q) .

The greatest resultant of two vectors vec P and vec Q is (n) times their least reast resultant. Fiven | vec P | gt |vec Q| . When theta is the angle between the two vectors, their resultant is half the sum of the two vectors. Show that, cos theta =- (n^(2) +2) // (n n^(2) -1) .

If the resultant of two vectors vec P and vec Q is given by R^(2) = P^(2) + Q^(2) , then the angle between the vectors vec P and vec Q is _____.