48.A bar magnet of "10cm" long is kept with its "N" -pole pointing north A neutral point is formed at a distance of "15cm" from each pole.Given the horizontal component of Earth's field is "0.4Gauss" ,The pole strength of the magnet is

A short bar magnet is placed in the magnetic meridian with its north pole pointing towards geographical south. A neutral point is found at a distance of 30 cm from the centre of the magnet. If the horizontal component of earth's field is 0.4G , calculate the magnetic moment of the magnet .

A bar magnet is placed with its north pole towards geographic north. The neutral point

A bar magnet 30cm long is placed in magnetic meridian with its north pole pointing south. The neutral point is observed at a distance of 30cm from its centre. Calculate the pole strength of the magnet. Given horizontal component of earth's field is 0*34G .

A bar magnet 30 cm long is placed in the magnetic meridian with its north pole pointing geographical south . The neutral point is found at a distance of 30 cm from its centre . Calculate the pole strength of the magnet . Given B_(H) = 0.34 G .

A short bar magnet of magnetic moment 0*5JT^-1 is placed with its magnetic axis in magnetic meridian, with its north pole pointing geographic north. A neutral point is obtained at a distance of 0*1m from the centre of the magnet. Find the horizontal component of earth's magnetic field.

A short bar magnet of magnetic moment 0*5JT^-1 is placed with its magnetic axis in the magnetic meridian, with its north pole pointing geographic north. A neutral point is obtained at a distance of 0*1m from the centre of the magnet. Find the horizontal component of earth's magnetic field.

A short bar magnet is placed along N-S direction with N pole pointing north. The neutral points are located 20 cm away from the bar magnet. If B_(H) is the horizontal component of earth's magnetic field then the magnetic field due to the bar magnet at distance of 40 cm along its axis is