The number of Li atoms in _____________ g. is `6.022xx10^(24)` atoms.

Answer

To determine the number of grams of lithium (Li) that corresponds to \(6.022 \times 10^{24}\) atoms, we can follow these steps:

### Step 1: Understand the concept of moles
1 mole of any substance contains \(6.022 \times 10^{23}\) entities (atoms, molecules, etc.), which is known as Avogadro's number.

### Step 2: Calculate the number of moles corresponding to \(6.022 \times 10^{24}\) atoms
To find out how many moles correspond to \(6.022 \times 10^{24}\) atoms, we can use the formula:
\[ \text{Number of moles} = \frac{\text{Number of atoms}}{\text{Avogadro's number}} = \frac{6.022 \times 10^{24}}{6.022 \times 10^{23}} \]

### Step 3: Simplify the calculation
When we divide \(6.022 \times 10^{24}\) by \(6.022 \times 10^{23}\), we can simplify:
\[ \text{Number of moles} = \frac{6.022}{6.022} \times \frac{10^{24}}{10^{23}} = 1 \times 10^{1} = 10 \text{ moles} \]

### Step 4: Convert moles to grams
Now, we need to convert moles of lithium to grams. We know that 1 mole of lithium weighs approximately 7 grams. Therefore, for 10 moles:
\[ \text{Mass in grams} = \text{Number of moles} \times \text{Molar mass} = 10 \text{ moles} \times 7 \text{ g/mole} = 70 \text{ grams} \]

### Final Answer
Thus, the number of Li atoms in \(70\) grams is \(6.022 \times 10^{24}\) atoms.

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