Number of atoms of oxygen in 24 g of `O_(3)` is _____________

Answer

To find the number of atoms of oxygen in 24 g of ozone (O₃), we can follow these steps:

### Step 1: Determine the molar mass of O₃
Ozone (O₃) consists of 3 oxygen atoms. The atomic mass of oxygen is approximately 16 g/mol. Therefore, the molar mass of O₃ is calculated as follows:

\[ \text{Molar mass of O}_3 = 3 \times 16 \, \text{g/mol} = 48 \, \text{g/mol} \]

### Step 2: Calculate the number of moles of O₃ in 24 g
Using the molar mass, we can find the number of moles of O₃ in 24 g:

\[ \text{Number of moles of O}_3 = \frac{\text{mass}}{\text{molar mass}} = \frac{24 \, \text{g}}{48 \, \text{g/mol}} = 0.5 \, \text{moles} \]

### Step 3: Calculate the number of oxygen atoms in O₃
Since each molecule of O₃ contains 3 oxygen atoms, the total number of oxygen atoms in 0.5 moles of O₃ can be calculated using Avogadro's number (approximately \(6.022 \times 10^{23}\) molecules/mol):

\[ \text{Number of oxygen atoms} = \text{Number of moles of O}_3 \times 3 \times \text{Avogadro's number} \]

Substituting the values:

\[ \text{Number of oxygen atoms} = 0.5 \, \text{moles} \times 3 \times 6.022 \times 10^{23} \, \text{atoms/mol} \]

\[ = 0.5 \times 3 \times 6.022 \times 10^{23} = 9.033 \times 10^{23} \, \text{oxygen atoms} \]

### Final Answer
The number of atoms of oxygen in 24 g of O₃ is \(9.033 \times 10^{23}\).

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