Which one act as strong oxidising agent `K^(+)//K=-2.93V, Ag^(+)//Ag=0.80, Hg^(2+)//Hg=0.79V`

Options

A. `K^(+)`
B. K
C. `Hg^(2+)`
D. `Ag^(+)`

Answer

To determine which ion acts as a strong oxidizing agent among the given options, we need to analyze the standard electrode potentials (E°) provided for each half-reaction.

### Step-by-Step Solution:

1. **Identify the Standard Electrode Potentials**:
- Potassium (K⁺/K): E° = -2.93 V
- Silver (Ag⁺/Ag): E° = +0.80 V
- Mercury (Hg²⁺/Hg): E° = +0.79 V

2. **Understand the Concept of Oxidizing Agents**:
- An oxidizing agent is a substance that gains electrons in a redox reaction and is reduced. The strength of an oxidizing agent is directly related to the standard electrode potential (E°). The higher (more positive) the E° value, the stronger the oxidizing agent.

3. **Compare the Electrode Potentials**:
- Among the given values, we can see:
- K⁺ has a negative potential (-2.93 V), indicating it is a weak oxidizing agent.
- Ag⁺ has a positive potential (+0.80 V), indicating it is a strong oxidizing agent.
- Hg²⁺ also has a positive potential (+0.79 V), but it is less than that of Ag⁺.

4. **Determine the Strongest Oxidizing Agent**:
- Since Ag⁺ has the highest positive E° value (+0.80 V), it is the strongest oxidizing agent among the three options.

5. **Conclusion**:
- Therefore, the strongest oxidizing agent is **Ag⁺ ions**.

### Final Answer:
**Ag⁺ ions act as the strongest oxidizing agent.**

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