In the reaction `6CIO_(2)^(-)rarr 4CIO_(3)^(-)+2CI^(-), CI^(-)` ion is

Options

A. Oxidised
B. Reduced
C. Odixised and reduced
D. Neither Oxidised nor reduced

Answer

To determine the oxidation state changes of chlorine in the reaction \(6 \text{ClO}_2^- \rightarrow 4 \text{ClO}_3^- + 2 \text{Cl}^-\), we will analyze the oxidation states of chlorine in each species involved in the reaction.

### Step 1: Determine the oxidation state of chlorine in \(\text{ClO}_2^-\)

Let the oxidation state of chlorine in \(\text{ClO}_2^-\) be \(x\). The oxidation state of oxygen is \(-2\).

Using the formula for the overall charge:
\[ x + 2(-2) = -1 \]
This simplifies to:
\[ x - 4 = -1 \implies x = +3 \]
Thus, the oxidation state of chlorine in \(\text{ClO}_2^-\) is \(+3\).

### Step 2: Determine the oxidation state of chlorine in \(\text{ClO}_3^-\)

Let the oxidation state of chlorine in \(\text{ClO}_3^-\) also be \(x\). Again, the oxidation state of oxygen is \(-2\).

Using the formula for the overall charge:
\[ x + 3(-2) = -1 \]
This simplifies to:
\[ x - 6 = -1 \implies x = +5 \]
Thus, the oxidation state of chlorine in \(\text{ClO}_3^-\) is \(+5\).

### Step 3: Determine the oxidation state of chlorine in \(\text{Cl}^-\)

For the chloride ion \(\text{Cl}^-\), the oxidation state is simply:
\[ -1 \]
Thus, the oxidation state of chlorine in \(\text{Cl}^-\) is \(-1\).

### Step 4: Analyze the changes in oxidation states

Now, we can summarize the changes in oxidation states of chlorine in the reaction:

- In \(\text{ClO}_2^-\) (reactant), the oxidation state of chlorine is \(+3\).
- In \(\text{ClO}_3^-\) (product), the oxidation state of chlorine is \(+5\) (oxidation).
- In \(\text{Cl}^-\) (product), the oxidation state of chlorine is \(-1\) (reduction).

### Conclusion

In this reaction, chlorine undergoes both oxidation (from \(+3\) to \(+5\)) and reduction (from \(+3\) to \(-1\)). Therefore, the answer is that chlorine is both oxidized and reduced.

### Final Answer

Chlorine ion (\(\text{Cl}^-\)) is **oxidized and reduced**.

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