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The K(sp) for AgCl at 298 K is 1.0xx10^(...

The `K_(sp)` for AgCl at 298 K is `1.0xx10^(-10)`. Calculate E for `Ag^(+)//Ag` electrode immersed in 1.0 M KCl solution.
Given : `E^(@)Ag^(+)//Ag=0.799" V"`.

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`AgCl(s)hArr Ag^(+)+Cl^(-)`
`K_(sp)=[Ag^(+)][Cl^(-)]`
`[Cl^(-)]=1.0M`
`[Ag^(+)]=(k_(sp))/([Cl^(-)])=(1xx10^(-10))/(1)=1xx10^(-10)M`
`"Now, "Ag^(+)+e^(-)rarrAg(s)`
`E=E^(theta)-(0.059)/(1)log.(1)/([Ag^(+)])`
`=0.80-(0.059)/(1)log.(1)/(10^(-10))`
`=0.80-0.059xx10=0.21V`
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