Calculate the potential of the cell at 298 K :
`Cd//Cd^(2+)(0.1M)||H^(+)(0.2M)//Pt, H_(2)(0.5atm)`
`"Given "E^(@)" for "Cd^(2+)//Cd=-0.403V, R=8.314J^(-1)" mol"^(-1), F="96500 C mol"^(-1)`.

Explanation

To calculate the potential of the cell at 298 K for the given electrochemical cell, we will follow these steps:

### Step 1: Identify the half-reactions
For the cell notation `Cd//Cd^(2+)(0.1M)||H^(+)(0.2M)//Pt, H_(2)(0.5atm)`, we can identify the half-reactions:
- Oxidation half-reaction:
\[ \text{Cd} \rightarrow \text{Cd}^{2+} + 2e^- \]
...