Deduce the structure of `XeF_(6)` using VSEPR theory.

Explanation

To deduce the structure of `XeF_(6)` using VSEPR theory, we will follow these steps:

### Step 1: Determine the number of valence electrons
- **Xenon (Xe)** has 8 valence electrons.
- **Fluorine (F)** has 7 valence electrons, and since there are 6 fluorine atoms, we have:
\[ 7 \text{ (F)} \times 6 = 42 \text{ valence electrons from F} \]
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