(b ) Draw the structures of `Cr_(2) O_(7)^(2-) , CrO_(4)^(-2) MnO_(4)^(-)`

Explanation

To draw the structures of the given compounds \( \text{Cr}_2\text{O}_7^{2-} \), \( \text{CrO}_4^{2-} \), and \( \text{MnO}_4^{-} \), we will follow a systematic approach to determine the oxidation states and the arrangement of atoms in each ion.

### Step 1: Determine the oxidation state of Chromium in \( \text{Cr}_2\text{O}_7^{2-} \)

1. Let the oxidation state of Cr be \( x \).
2. The total contribution from oxygen (7 O atoms) is \( 7 \times (-2) = -14 \).
3. The overall charge of the ion is -2.
4. Set up the equation:
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