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H(3)C-underset(CH(3))underset(|)(CH)-CH=...

`H_(3)C-underset(CH_(3))underset(|)(CH)-CH=CH_(2)+HBr to A`.
A is predominantly

A

`H_(3)C - underset(CH_(3))underset(|)overset(Br)overset(|)(CH)-CH_(2) - CH_(3)`

B

`H_(3)C - underset(Br)underset(|)overset(Br)overset(|)((CH)-underset(CH_(3))underset(|)(CH) - CH_(3)`

C

`H_(3) C - underset(CH_(3))underset(|)overset(Br)overset(|)(CH)-underset(Br)underset(|)(CH)-CH_(3)`

D

`CH_(3)-underset(CH_(3))underset(|)overset(Br)overset(|)(CH)-CH_(2)-CH_(2)-Br`

Text Solution

Verified by Experts

The correct Answer is:
A
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