Draw the structure of 4-bromo-3-methylpent-2-ene.

Answer

To draw the structure of 4-bromo-3-methylpent-2-ene, we will follow these steps:

### Step 1: Identify the main chain
The name "pent" indicates that the main carbon chain consists of 5 carbon atoms. Therefore, we will start by drawing a straight chain of 5 carbon atoms.

**Hint:** The prefix "pent" in the name indicates a 5-carbon chain.

### Step 2: Number the carbon chain
We need to number the carbon chain to locate the double bond and the substituents correctly. The double bond is indicated by "2-ene," which means it is located between the second and third carbon atoms. We will number the chain from the end closest to the double bond.

1. C1
2. C2
3. C3
4. C4
5. C5

**Hint:** Number the carbon chain from the end closest to the double bond to ensure correct positioning of substituents.

### Step 3: Place the double bond
Since the double bond is in the second position, we will draw the double bond between C2 and C3.

**Hint:** The "2-ene" indicates that the double bond is between the second and third carbon atoms.

### Step 4: Add the substituents
Next, we need to add the substituents:
- The "4-bromo" indicates a bromine (Br) atom is attached to the fourth carbon (C4).
- The "3-methyl" indicates a methyl (CH₃) group is attached to the third carbon (C3).

So, we will add:
- A bromine atom to C4.
- A methyl group (CH₃) to C3.

**Hint:** The substituents are added based on their positions indicated in the name.

### Step 5: Complete the structure with hydrogen atoms
Now we need to fill in the remaining hydrogen atoms to satisfy the tetravalency of carbon. Each carbon can form four bonds, so we will add hydrogen atoms where needed.

- C1 will have 3 H atoms (CH₃).
- C2 will have 1 H atom (due to the double bond).
- C3 will have 1 H atom (due to the methyl group).
- C4 will have 1 H atom (due to the bromine substituent).
- C5 will have 3 H atoms (CH₃).

**Hint:** Ensure that each carbon has four bonds by adding hydrogen atoms where necessary.

### Final Structure
The final structure of 4-bromo-3-methylpent-2-ene is:

```
Br
|
CH3-C=C-CH-CH3
|
CH3
```

### Summary of Steps:
1. Identify the main chain (pent).
2. Number the carbon chain.
3. Place the double bond in the correct position.
4. Add the substituents (bromo and methyl).
5. Complete the structure with hydrogen atoms.