Home
Class 12
CHEMISTRY
An organic compound A reacts with PCl(5)...

An organic compound A reacts with `PCl_(5)` to give compound B. Compound B reacts with Na/ether to give n-butane. What are compounds A and B ?

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will identify the compounds A and B based on the given reactions. ### Step 1: Identify the final product The final product mentioned in the question is n-butane (C₄H₁₀). This indicates that the reaction leading to butane must involve a precursor that can yield butane through a specific reaction mechanism. **Hint:** Look for reactions that can produce butane from smaller alkyl halides. ### Step 2: Understand the reaction with Na/ether The reaction of compound B with sodium (Na) in dry ether suggests a Wurtz reaction. In the Wurtz reaction, two alkyl halides react with sodium to form a higher alkane. Since the final product is butane (C₄H₁₀), we can infer that compound B must be a bromo- or chloro-alkane with two carbon atoms (C₂H₅Cl or C₂H₅Br) because two of these would combine to form butane. **Hint:** Recall the Wurtz reaction and how it combines two alkyl halides. ### Step 3: Determine compound B Based on the above reasoning, compound B must be chloroethane (C₂H₅Cl). This is because when two molecules of chloroethane react with sodium in dry ether, they will produce butane: \[ 2 \text{C}_2\text{H}_5\text{Cl} + 2 \text{Na} \rightarrow \text{C}_4\text{H}_{10} + 2 \text{NaCl} \] **Hint:** Identify the structure of chloroethane and how it can lead to butane. ### Step 4: Identify compound A Now, we need to find compound A, which reacts with PCl₅ to form compound B (C₂H₅Cl). PCl₅ is known to convert alcohols into alkyl chlorides. Therefore, compound A must be an alcohol that, when treated with PCl₅, yields chloroethane. The alcohol that corresponds to chloroethane is ethanol (C₂H₅OH). The reaction can be represented as follows: \[ \text{C}_2\text{H}_5\text{OH} + \text{PCl}_5 \rightarrow \text{C}_2\text{H}_5\text{Cl} + \text{by-products} \] **Hint:** Think about common alcohols that can be converted to alkyl halides. ### Final Answer Thus, the compounds are: - Compound A: Ethanol (C₂H₅OH) - Compound B: Chloroethane (C₂H₅Cl)
Promotional Banner

Topper's Solved these Questions

  • HALOALKANES AND HALOARENES

    CBSE COMPLEMENTARY MATERIAL|Exercise SHORT ANSWER-II TYPE QUESTIONS (3 Marks)|18 Videos
  • HALOALKANES AND HALOARENES

    CBSE COMPLEMENTARY MATERIAL|Exercise LONG ANSWER TYPE QUESTIONS (5 Marks)|5 Videos
  • HALOALKANES AND HALOARENES

    CBSE COMPLEMENTARY MATERIAL|Exercise VERY SHORT ANSWER TYPE QUESTIONS (1 Mark)|19 Videos
  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    CBSE COMPLEMENTARY MATERIAL|Exercise Short Answer-II Type Questions|5 Videos
  • P-BLOCK ELEMENTS

    CBSE COMPLEMENTARY MATERIAL|Exercise LONG ANSWER TYPE QUESTIONS|15 Videos

Similar Questions

Explore conceptually related problems

Which compound reacted with CO_2 gives an organic compound?

Compound (A) racts with SOCl_2 to give compound (B). The compound (B) reacts with Mg metal give Grignard's reagent , which is treated with acetone and product is hydrolysed to give 2-methyl-2-butanol . What is (A)?

An organic compound [A] is C_(5)H_(8)O_(3). On heating with soda lime, it gives [B]. The compound [B] reacts with HCN to give another compound [C] which reacts with thionyl chloride to produce [D]. When the compound [A] is heated with potassium dichromate the product is acetic acid and malonic acid. The compound [A] is a

An organic compound [A] is C_(5)H_(8)O_(3). On heating with soda lime, it gives [B]. The compound [B] reacts with HCN to give another compound [C] which reacts with thionyl chloride to produce [D]. When the compound [A] is heated with potassium dichromate the product is acetic acid and malonic acid. The structure of compound [A] is :

Compound A reacts with Na metal to give B. A also reacts with PCl_(5) to give C. B and C reacts with each other to give dimethyl ether. Then A, B and C respectively are

CBSE COMPLEMENTARY MATERIAL-HALOALKANES AND HALOARENES-SHORT ANSWER-I TYPE QUESTIONS (2 Marks)
  1. Complete the following reactions : (i) C(6)H(5)N(2)CI + KI to (ii)

    Text Solution

    |

  2. Carry out the following conversions in not more than two steps : (i)...

    Text Solution

    |

  3. Give reasons : (i) Boiling point of alkyl bromide is higher than alk...

    Text Solution

    |

  4. Which of the following compounds would undergo SN(1) reaction faster a...

    Text Solution

    |

  5. Identify and indicate the presence of centre of chirality, if any, in ...

    Text Solution

    |

  6. Convert : (i) Benzene to m-nitrochlorobenzene (ii) Benzene to diph...

    Text Solution

    |

  7. What happens when : (i) Propene is treated with HBr in presence of p...

    Text Solution

    |

  8. (i) Alkyl iodides develop colouration on long standing particularly in...

    Text Solution

    |

  9. tert-Butylbromide reacts with aq. NaOH by S(N)1 mechanism while n but...

    Text Solution

    |

  10. Althrough chlorine is an electron withdrawing group, yet it is ortho-p...

    Text Solution

    |

  11. Identify the products : (i) + Mg underset("ether")overset("dry")...

    Text Solution

    |

  12. (i) Arrange the following halides in order of increasing S(N)^(1) reac...

    Text Solution

    |

  13. Identify the products : C(6)H(6) underset("anhy" ALCI(3))overset(CH(...

    Text Solution

    |

  14. Carry out the following conversions : (i) But-1-ene to n-butyliodide...

    Text Solution

    |

  15. An organic compound A reacts with PCl(5) to give compound B. Compound ...

    Text Solution

    |

  16. Write short note on : (i) Sandmeyer reaction (ii) Finkelstein reac...

    Text Solution

    |

  17. Name the reagents used to convert : (i) 2-chloropropane to 2-nitropr...

    Text Solution

    |

  18. Draw structure of monohalo product in each of the following :

    Text Solution

    |