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The treatment of alkyl chlorides with aq...

The treatment of alkyl chlorides with aqueous KOH leads to the formation of alcohols but in the presence of alcoholic KOH, alkenes are major products. Explain.

Text Solution

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In aqueous KOH,OH– is nucleophile which replaces another nucleophile.
`R-X + KOH to R - OH + KX`
Where as in alcoholic KOH, `C_(2)H_(5)O`– ion is produced which is a strong base hence `beta`-elimination took place to form alkane
`C_(2)H_(5) OH + COH to C_(2)H_(5)O_(-) + K^(+)`
`CH_(3)CH_(2) - CI` + alcoholic KOH` to CH_(2) = CH_(2) + C_(2)H_(5)OH`
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