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Solution set for inequality |x-1|le5is....

Solution set for inequality `|x-1|le5`is.

A

[-6,4]

B

[-4,0]

C

[-4,6]

D

[0,6]

Text Solution

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The correct Answer is:
To solve the inequality \( |x - 1| \leq 5 \), we will follow these steps: ### Step 1: Understand the Absolute Value Inequality The expression \( |x - 1| \leq 5 \) means that the distance between \( x \) and \( 1 \) on the number line is at most \( 5 \). This leads to two inequalities: \[ -5 \leq x - 1 \leq 5 \] ### Step 2: Break it into Two Inequalities From the absolute value inequality, we can split it into two separate inequalities: 1. \( x - 1 \leq 5 \) 2. \( x - 1 \geq -5 \) ### Step 3: Solve the First Inequality Now, we solve the first inequality: \[ x - 1 \leq 5 \] Adding \( 1 \) to both sides gives: \[ x \leq 6 \] ### Step 4: Solve the Second Inequality Next, we solve the second inequality: \[ x - 1 \geq -5 \] Adding \( 1 \) to both sides gives: \[ x \geq -4 \] ### Step 5: Combine the Results Now we combine the results from both inequalities: \[ -4 \leq x \leq 6 \] This can be written in interval notation as: \[ [-4, 6] \] ### Final Solution Thus, the solution set for the inequality \( |x - 1| \leq 5 \) is: \[ [-4, 6] \] ---
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