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2x+yle 24,x+yle11,2x+5yle40,xge 0, y ge ...

`2x+yle 24,x+yle11,2x+5yle40,xge 0, y ge 0`

Answer

Step by step text solution for 2x+yle 24,x+yle11,2x+5yle40,xge 0, y ge 0 by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.

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Knowledge Check

  • The maximum vlaue of Z = 9x+13y subject to constraints 2x+3yle 18, 2x+y le 10, x ge 0, y ge 0 is

    A
    130
    B
    81
    C
    79
    D
    28

  • The common region represented by inequalities yle2,x+yle3,-2x+yle1,xge0,yge0 is

    A
    a triangle
    B
    a quadrilateral
    C
    a square
    D
    a pentagon

  • The objective function z=4x+3y subject to 3x+4yle24,8x+6yle48,xle5,yle6,xge0,yge0 can be maximized

    A
    at only one point
    B
    at two points only
    C
    at infinite number of points
    D
    at three points only

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    Find the maximum and minimum values of Z=2x+y, subject to the constraints x+3y ge6, x+3y le3,3x+4yle24, -2x+2yle6,5x+yge5,x ge0and y ge0.

    Shaded, region of the constraints x+yge5,2x+3yle18,4x+3yle24,xge0,yge0 is

    The graphical solution of the inequalities x+2yle10,x+yge1,x-yle0,xge0,yge0 is

    The solution of set of constraints x+2yge11,3x+4yle30,2x+5yle30,xge0,yge0 includes the point

    The minimum value of z=x+2y subject to x+2yge50,2x-yle0,2x+yle100,xge0,yge0 is

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