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A bullet of mass m moving with a speed v...

A bullet of mass m moving with a speed v strikes a wooden block of mass M & gets embedded into the block. The final speed is

A

`sqrt((M)/(M+n))V`

B

`sqrt((m)/(M+n))V`

C

`(m)/(M+n) V`

D

`V/2`

Text Solution

Verified by Experts

The correct Answer is:
C
By Law of conservation of momentum
mv+M(0)=(m+M)V
`V=(mv)/(m+M)`
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Knowledge Check

  • A bullet of mass m moving with velocity v strikes a block of mass M at rest and gets embedded into it. The kinetic energy of the composite block will be

    A
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