A bullet of mass m moving with a speed v strikes a wooden block of mass M & gets embedded into the block. The final speed is

Options

A. `sqrt((M)/(M+n))V`
B. `sqrt((m)/(M+n))V`
C. `(m)/(M+n) V`
D. `V/2`

Answer

C

Explanation

By Law of conservation of momentum
mv+M(0)=(m+M)V
`V=(mv)/(m+M)`