A bullet of a mass 0.02 kg is moving with a speed of `10ms^(-1)`. It can penetrate 10 cm of a wooden block, and comes to rest. If the thickness of the target would be 6 cmonly, find the K.E. of the bullet when it comes out.

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Identify the given values
- Mass of the bullet, \( m = 0.02 \, \text{kg} \)
- Initial speed of the bullet, \( u = 10 \, \text{m/s} \)
- Distance penetrated in the first scenario, \( s_1 = 10 \, \text{cm} = 0.10 \, \text{m} \)
- Distance penetrated in the second scenario, \( s_2 = 6 \, \text{cm} = 0.06 \, \text{m} \)

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