An elevator which can carry a maximum load of 1800 kg (elevator + passenger) is moving up with a constant speed of `2ms^(-1)`. The frictional force opposing the motion is 4000 N. Determine the minimum power delivered by the motor to the elevator in watts as well as in horse power.

Explanation

To solve the problem, we need to determine the minimum power delivered by the motor to the elevator. The steps involved are as follows:

### Step 1: Identify the forces acting on the elevator
The forces acting on the elevator are:
- The gravitational force (weight) acting downwards, which is given by \( F_g = mg \).
- The frictional force opposing the motion, which is given as \( F_r = 4000 \, \text{N} \).

### Step 2: Calculate the weight of the elevator
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