A mass of `5kg` is moving along a circular path or radius `1m`. If the mass moves with 300 revolutions per minute, its kinetic energy would be

Options

A. `250pi^(2)`
B. `100 pi^(2)`
C. `5 pi^(2)`
D. `0`

Answer

A

Explanation

`V=omegaR,omega=(2pi)/T=10 pi "rod"//s`
`V=10 pi ms^(-1)impliesK.E=1/2 mv^(2)=250pi^(2)J`