A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?

Options

A. 3 cm
B. 2.0 cm
C. 1.5 cm
D. 1.0 cm

Answer

D

Explanation

`W=DeltaK`
Case I: `Fxx3=1/2m((V_(0))/2)^(2)-1/2 mV^(2)`
Where `Fto` resistive force
`V_(0)to` initial velocity
Case II: Let further distance be s
`-F(3+s)=K_(f)-K_(i)=-1/2 mV_(0)^(2)`
`S=1cm`