If linear momentum if increased by `50%` then kinetic energy will be increased by

Options

A. 0.5
B. 1
C. 1.25
D. 0.25

Answer

C

Explanation

`P^(1)=1.5P`, initial K.E. `=(P^(2))/(2m)`, Find K.E. `K^(-1)=(P^(12))/(2m)`
`K^(1)=2.25`
% increase `=(DeltaK)/Kxx100=125%`