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Four point masses, each of value m, are placed at the corners of a square ABCD of side l. The moment of inertia of this system about an axis passing through A and parallel to BD is

A

`3 ml^(2)`

B

`ml^(2)`

C

`2ml^(2)`

D

`sqrt(3)ml^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`AC = BD = sqrt(2)l`
`I_(BD) = m(AO)^(2) + m(CO)^(2) = ml^(2)`
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