When a satellite is moving around the earth with velocity `v`, then to make the satellite escape, the minimum percentage increase in its velocity should be

Explanation

The maximum orbital velocity of a satellite orbiting near its surface is
`v_(0)= sqrt(gR)= (v_e)/(sqrt(2))`
For the satellite to escape gravitational pull the velocity must become `v_e`
But `v_e= sqrt(2)v_(0) =1.414 v_(0)= (1+0.414)v_(0)`
This means that it has to increases 0.414 in 1 or 41.4%.
The minimum increment is required, as the velocity of satellite is maximum when it is near the earth.