Home
Class 11
PHYSICS
A body released at the distance r(r gt R...

A body released at the distance `r(r gt R)` from the centre of the earth. What is the velocity of the body when it strikes the surface of the earth?

Text Solution

AI Generated Solution

To find the velocity of a body when it strikes the surface of the Earth after being released from a distance \( r \) (where \( r > R \), with \( R \) being the radius of the Earth), we can use the principle of conservation of energy. Here’s a step-by-step solution: ### Step 1: Understand the Energy Conservation Principle The total mechanical energy (potential energy + kinetic energy) of the body remains constant if we ignore air resistance. Initially, the body has gravitational potential energy and no kinetic energy since it is released from rest. ### Step 2: Calculate Initial Potential Energy The gravitational potential energy \( U \) at a distance \( r \) from the center of the Earth is given by: \[ ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    CBSE COMPLEMENTARY MATERIAL|Exercise MULTIPLE CHOICE QUESTIONS|19 Videos
  • GRAVITATION

    CBSE COMPLEMENTARY MATERIAL|Exercise LONG ANSWER TYPE QUESTIONS (5 MARKS)|6 Videos
  • DIMENSIONS AND MEASUREMENT

    CBSE COMPLEMENTARY MATERIAL|Exercise M.C.Q PHYSICAL WORLD & MEASUREMENT|20 Videos
  • KINEMATICS

    CBSE COMPLEMENTARY MATERIAL|Exercise M.C.Q.|20 Videos

Similar Questions

Explore conceptually related problems

Statement-1 : A body released from a height equal to the radius (R ) of the earth. The velocity of the body when it strikes the surface of the earth will be sqrt(2 g R) . Statement -2 : As upsilon^(2) = u^(2) + 2 as.

The gravitational potential energy at a body of mass m at a distance r from the centre of the earth is U. What is the weight of the body at this distance ?

A body at rest starts from a point at a distance r (gtR) from the centre of the Earth. If M and R stand for the speed of the body when it reaches the Earth surface is

The escape velocity of a body from the surface of the earth is equal to

The satellite is moving round the earth (radius of earth = R) at a distance r from the centre of the earth. If g is the acceleration due to gravity on the surface of the earth. The acceleration of the satellite will be

The escape velocity of a body from the surface of earth is

A body is released from a point of distance R' from the centre of earth. Its velocity at the time of striking the earth will be (R’gtR_(e))

The earth has mass M and radius R .An object of mass m is dropped from a distance of 3R , from the centre of the earth.The object strikes the surface of the earth with a speed , v=sqrt(kgR) ,where g is acceleration due to gravity or the surface of the earth.The value of k

A tunnel is dug across the earth of mass 'M' and radius 'R' at a distance R//2 from the centre 'O' of the Earth as shown. A body is released from rest from one end of the smooth tunnel. The velocity acquired by the body when it reaches the centre 'C' of the tunnel is

The acceleration of a body due to the attraction of the earth (radius R) at a distance 2R form the surface of the earth is (g=acceleration due to gravity at the surface of the earth)