Calculate the fall in temperature when a gas initially at `72^@C` is expanded suddenly to eight times its original volume. `(gamma = 5//3)`

Explanation

To solve the problem of calculating the fall in temperature when a gas initially at \(72^\circ C\) is expanded suddenly to eight times its original volume, we will use the adiabatic process equations. Here are the steps:

### Step 1: Convert the initial temperature to Kelvin
The initial temperature \(T_1\) is given as \(72^\circ C\). To convert this to Kelvin, we use the formula:
\[ T(K) = T(°C) + 273 \]
So,
...