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A gas is found to obey the law P^(2)V = ...

A gas is found to obey the law `P^(2)V = constant`. The initial temperature and volume are `T_(0) and V_(0)`. If the gas expands to a volume `3 V_(0)`, its final temperature becomes

A

`(To)/(3)`

B

`(To)/(sqrt(3))`

C

`3 To`

D

`sqrt(3)To`

Text Solution

Verified by Experts

The correct Answer is:
D
`P^(2)V=` constant `implies((RT)/(V))^(2) V=` constant `implies(T^(2))/(V)` constant
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