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Calculate the energy in fusion reaction:...

Calculate the energy in fusion reaction:
`""_(1)H^(2) + ""_(1)H^(2) to ""_(2)He^(3) + ""_(0)n^(1)`, where B.E. Of `""_(1)H^(2) = 2.23 `MeV and `""_(2)He^(3) = 7.73` MeV.

Text Solution

Verified by Experts

Initial binding energy
`BE_1 = (2.23 + 2.23) = 4.46 MeV`
Final binding energy
`BE_2 = 7.73 MeV`
Energy released = (7.73 – 4.46) MeV= 3.27 MeV
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