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At a place, the horizontal component of ...

At a place, the horizontal component of earth's magnetic field is B and angle of dip is `60^@`. What is the value of horizontal component of earth's magnetic field at equator?

Text Solution

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`B_(H)=B_(E) cos delta`
`B=B_(E)cos 60^(@)impliesB_(E)=2B`
Aq equator `delta=0^(@)`
`:.B_(H)=2Bcos0^(@)=2B`
[Alternativ\ely, Award full one mark, if student doesn't the value `(=2B)` of `B_(E)` while finding the value of horizontal component of equator, and just writes and formula only.]
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