Find out the wavelength of the electron orbiting in the ground state of hydrogen atoms.

Explanation

Calculation of wavelength of electron in ground state
Radiusd of ground state of hydrogen atom `=0.53Å=0.53xx10^(-10)m`
According to be Broglie relation`2nr=n lamda`
For gorund state `n=1`
`2xx3.14xx0.53xx10^(-10)=1xxlamda `
`:.lamda=3.32xx10^(-10)m`
`=3.32Å`
Alternatively
Velocity of electron, in the ground state, of hydrogen atom `=2.18xx10^(-6)m//s`
Hence momentum of revolving electron
`p=mv`
`=9.1xx10^(-31)xx2.18xx10^(-5)kgm//s`
`lamda=h/p=(6.63xx10^(-24))/(9.0xx10^(-31)xx2.18xx10^(6))m`
`-3.32A`