The current is drawn from a cell of emf E and iternal resitance r connected to the network of resistors each of resistor r as shown in the figure. Obtain the expression for (i) the current draw from the cell and (ii) the power consumed in the network.

Explanation

Equivalent resistance of the loop
`R=r//3`
Hence current drawn from the cell
`I=E/(r//3+r)=(3E)/(4r)`
Power consumed
`P=I^(2)(r//3)`
`=(9E^(2))/(r//3+r)=(3E)/(4r)`
Power consumed
`P=I^(2)(r//3)`
`=(9E^(2))/(16r^(2))xx4r//3=(3E^(2))/(4r)`