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An electron of kinetic energy 10 keV mov...

An electron of kinetic energy 10 keV moves perpendicular to the direction of a uniform magnetic field of 0.8 milli tesla. Calculate the time period of rotation of the electron in the magnetic field.

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To solve the problem of calculating the time period of rotation of an electron moving perpendicular to a magnetic field, we can follow these steps: ### Step 1: Understand the Given Information - Kinetic Energy (KE) of the electron = 10 keV - Magnetic Field (B) = 0.8 milliTesla = 0.8 x 10^-3 Tesla ### Step 2: Convert Kinetic Energy to Joules The kinetic energy in joules can be calculated using the conversion: ...
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CBSE COMPLEMENTARY MATERIAL-UNIT–III & UNIT–IV MAGNETIC EFFECTS OF CURRENT AND MAGNETISM & E.M.I. AND ALTERNATING CURRENT-(NUMERICALS)
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